Answer:
C) 2094.40
nearest answer.
Step-by-step explanation:
Since the given region is bounded by y = x, y = 10 and x = 0
⇒ 0 ≤ y ≤ 10
Radius and Height are 'y'
∴ The required volume
= ∫₀¹⁰2π(radius)(height)dy
= ∫₀¹⁰2π (y) (y) dy
= ∫₀¹⁰2π y² dy
= 2π ∫₀¹⁰ y² dy
Integrate y
= [tex]2\pi [\frac{y^3}{3}]_0^{10}[/tex]
= [tex]2\pi [\frac{10^3}{3} - 0][/tex]
= [tex]\frac{2000}{3} \pi[/tex]
where π is 3.142
= 2,094.66
