The table of this question is in the attachments.
Answer and Step-by-step explanation: Standard deviation is a measure of how spread the data is from the mean. It is calculated as:
s = √∑(x - μ)² / n - 1
where μ is the mean of the set.
Range is the difference between the highest and lowest value of a data set.
(a) Range of Traditional course:
range = 80.4 - 56
range = 24.4
Range of "flipped" course:
range = 92.6 - 63.5
range = 29.1
Comparing ranges, the "flipped" course has more dispersion than the traditional.
(b) Standard Deviation of Traditional course:
mean = 71.6
s = [tex]\sqrt{\frac{(70.3 - 71.6)^{2}+...+(59.1-71.6)^{2}}{13-1}[/tex]
s = 8.95
Standard Deviation of "flipped" course:
mean = 77.6
s = [tex]\sqrt{\frac{(75.5 - 77.6)^{2}+...+(76.9-77.6)^{2}}{13-1}[/tex]
s = 8.3
Comparing standard deviation, traditional course has more dispersion.
(c) If you change one score, range for traditional will be:
range = 591 - 56
range = 535
Changing one score increase in almost 22 times the range for this category.
