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Working on this program in Python 3.7:A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:1) The year must be divisible by 42) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400Some example leap years are 1600, 1712, and 2016.Write a program that takes in a year and determines whether that year is a leap year.Ex: If the input is 1712, the output is:1712 is a leap year. Ex: If the input is 1913, the output is:1913 is not a leap year. Your program must define and call the function IsLeapYear(userYear). The function should return true if the input year is a leap year and false otherwise.

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NiranjanSaravanan
This year according to real calendar today is 12 January 2012
siouxfederation1

Answer:

def is_leap_year(year):

  if(year % 400 == 0):

      return True

  elif year % 100 == 0:

      return False

  elif year%4 == 0:

      return True

  else:

      return False  

if __name__ == '__main__':

  n = int(input())

  if(is_leap_year(n)):

      print(n,"is a leap year.")

  else:

      print(n, "- not a leap year")

Explanation:

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