Answer:
The probability that 45 randomly selected laptops will have a mean replacment time of 4.4 years or less is P(M<4.4)=0.0468.
Step-by-step explanation:
We have a population normally distributed with mean 4.5 years and standard deviation of 0.4 years.
Samples of size n=45 are selected from this population.
We have to calculate the probability that a sample mean is 4.4 years or less.
Then, we calculate the z-score for the sample mean M=4.4 and then calculate the probability using the standard normal distribution:
[tex]z=\dfrac{M-\mu}{\sigma/\sqrt{n}}=\dfrac{4.4-4.5}{0.4/\sqrt{45}}=\dfrac{-0.1}{0.06}=-1.677\\\\\\P(M<4.4)=P(z<-1.677)=0.0468[/tex]
The probability that 45 randomly selected laptops will have a mean replacment time of 4.4 years or less is P(M<4.4)=0.0468.