Answer:
[tex] \boxed{\huge {\sf y = 4a}} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: y: \\ \sf \implies 4y - 3a = 13a \\ \\ \sf Add \: 3a \: to \: both \: sides: \\ \sf \implies 4y + ( \boxed{ \sf 3a} - 3a) = \boxed{ \sf 3a} + 13a \\ \\ \sf 3a - 3a = 0 : \\ \sf \implies 4y = 3a + 13a \\ \\ \sf 3a + 13a = 16a : \\ \sf \implies 4y = 16a \\ \\ \sf Divide \: both \: sides \: by \: 4: \\ \sf \implies \frac{4y}{ \boxed{ \sf 4}} = \frac{16a}{ \boxed{ \sf 4}} \\ \\ \sf \frac{4y}{4} = \frac{ \cancel{ \sf 4}}{\cancel{ \sf 4}} \times y = y : \\ \sf \implies y = \frac{16a}{4} \\ \\ \sf \frac{16a}{4} = \frac{\cancel{ \sf 4} \times 4a}{\cancel{ \sf 4}} = 4a : \\ \sf \implies y = 4a[/tex]
