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Find two positive numbers whose product is 16 and whose sum is a minimum. (If both values are the same number, enter it into both blanks.) (smaller number) (larger number)

Respuesta :

jmonterrozar

Answer:

4 and 4

Step-by-step explanation:

We have 2 numbers that will be X and Y

X * Y = 16 => Y = 16 / X

We must minimize the sum, therefore:

S = X + Y

S = X + 16 / X

we derive and equal 0 and we are left with:

dS / dA = 1 - 16 / (X ^ 2) = 0

1 = 16 / X ^ 2

X ^ 2 = 16

X = 4

in the case of Y:

Y = 16/4 = 4

Therefore the numbers are 4 and 4.

abidemiokin

The two positive numbers are 4 and 4

Let the two numbers be x and y

If the product of both numbers is 16, hence;

xy = 16 ........................... 1

If the sum will be at the minimum, hence x + y = minimum

From equation1, x = 16/ y

Substitute into the second equation to have;

16/y + y = A(y)

A(y) = 16/y + y

For the expression to be at a minimum, hence dA/dy = 0

dA/dy = -16/y² + 1

0 = -16/y² + 1

0 - 1 =  -16/y²

-y² = -16

y = √16

y = 4

Recall that xy = 16

4x= 16

x = 4

Hence the two positive numbers are 4 and 4

LEarn more here: https://brainly.com/question/13598452

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