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A stock solution of HNO3 is prepared and found to contain 14.2 M of HNO3. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is ________ M.

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Answer:

First convert volume given into same unit.

Therefore 1000 mL =1L

1000mL=1L

25.0mL=?

(25.0×1)÷1000=0.025L

but using the equation;M1×V1=M2×V2

M1=14.2M

V1=0.025L

M2=?

V2=0.5L

Therefore;. 14.2×0.025=M2×0.5

M2=(14.2×0.025)÷0.5

M2=0.71M.

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