Respuesta :
Answer:
Explanation:
A )
molecular weight of KMnO₄ = 158
75 g KMnO4 = 75 / 158 moles
= ( 75 / 158 )x 6.02 x 10²³ molecules
= 2.857 x 10²³ molecules KMnO4
so 75g KMnO₄ = 2.857 x 10²³ molecules KMnO4
B )
7.23 × 10²⁴ Al atoms = grams Al
72.3 X 10²³ Al atoms = 72.3 X 10²³ / 6.02 X 10²³ moles of Al
= 12 moles of Al
= 12 x 27 gm of Al
= 324 gm of Al .
7.23 × 10²⁴ Al atoms = 324 grams Al
C )
9.23 × 10²³ Au atoms = moles Au
9.23 × 10²³Au atoms = 9.23 × 10²³ / 6.02 x 10²³ moles of Au
= 1.53 moles of Au .
D )
125 g H₃PO₄ = molecules H₃PO₄
125 g H₃PO₄ = 125 / 98 moles of H₃PO₄
= (125 / 98) x 6.02 x 10²³ molecules
= 7.678 x 10²³ molecules of H₃PO₄
125 g H₃PO₄ = 7.678 x 10²³ molecules H₃PO₄
E )
.75 moles of CO₂
= .75 x 6.02 x 10²³ molecules of CO₂
= 4.515 x 10²³ molecules of CO₂.
one molecule of CO₂ = 3 atoms
4.515 x 10²³ molecules of CO₂ = 3 x 4.515 x 10²³ atoms
= 13.545 x 10²³ atoms .
The molecules, atoms, and weight of all elements and compounds has been calculated.
(A) To calculate the molecules of a compound:
Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]
Moles = [tex]\rm \frac{weight}{molecular\; weight}[/tex]
Moles of [tex]\rm KMnO_4[/tex] = [tex]\rm \frac{75}{158}[/tex]
Moles of [tex]\rm KMnO_4[/tex] = 0.474
Molecules of [tex]\rm KMnO_4[/tex] = [tex]\rm 0.474\;\times\;6.023\;\times\;10^2^3[/tex]
Molecules of [tex]\rm KMnO_4[/tex] = 2.85 [tex]\rm \times\;10^2^3[/tex]
(B) Weight of Al:
moles = [tex]\rm \frac{atoms}{avagadro\;number}[/tex]
Moles of Al = [tex]\rm \frac{7.23\;\times\;10^2^4}{6.023\;\times\;10^2^3}[/tex]
Moles of Al = 12
Weight of Al = [tex]\rm moles\;\times\;molecular\;weight[/tex]
Weight of Al = 12 [tex]\times[/tex] 27
Weight of Al = 324 grams
(C) Moles = [tex]\rm \frac{atoms}{avagadro\;number}[/tex]
Moles of Au = [tex]\rm \frac{9.23\;\times\;10^2^3}{6.023\;\times\;10^2^3}[/tex]
Moles of Au = 1.53 mol/liters
(D) Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]
Moles = [tex]\rm \frac{weight}{molecular\; weight}[/tex]
Moles of [tex]\rm H_3PO_4[/tex] = [tex]\rm \frac{125}{98}[/tex]
Moles of [tex]\rm H_3PO_4[/tex] = 1.275
Molecules of [tex]\rm H_3PO_4[/tex] = 1.275 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]
Molecules of [tex]\rm H_3PO_4[/tex] = [tex]\rm 7.678\;\times\;10^2^3[/tex]
(E) Atoms of [tex]\rm CO_2[/tex]:
Molecules = [tex]\rm moles\;\times\;avagadro\;number[/tex]
Molecules of [tex]\rm CO_2[/tex] = 0.75 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]
Molecules of [tex]\rm CO_2[/tex] = 4.515 [tex]\rm \times\;10^2^3[/tex]
1 molecule of [tex]\rm CO_2[/tex] = 3 atoms
4.515 [tex]\rm \times\;10^2^3[/tex] molecules = [tex]\rm 4.515\;\times\;10^2^3\;\times\;3[/tex]
Atoms of [tex]\rm CO_2[/tex] = 13.545 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex]
For more information about the dimensional analysis conversion, refer the link:
https://brainly.com/question/13156854?referrer=searchResults
