Answer:
3) [tex]\frac{(25)^{3/2} * (243)^{3/5}}{(16)^{5/4}*(8)^{4/3}}[/tex]
=> [tex]\frac{(5^2)^{3/2}*(3^5)^{3/5}}{(2^4)^{5/4}*(2^3)^{4/3}}[/tex]
=> [tex]\frac{5^3*5^3}{2^5*2^4}[/tex]
=> [tex]\frac{5^6}{2^9}[/tex]
4) [tex]\frac{3-2\sqrt{2} }{3+2\sqrt{2} }[/tex]
Multiplying and dividing by conjugate [tex]3-2\sqrt{2}[/tex]
=> [tex]\frac{(3-2\sqrt{2})(3-2\sqrt{2}) }{(3+2\sqrt{2})(3-2\sqrt{2})}[/tex]
=> [tex]\frac{9-6\sqrt{2}-6\sqrt{2} +8 }{9-8}[/tex]
=> [tex]\frac{17-12\sqrt{2} }{1}[/tex]
=> [tex]17-12\sqrt{2}[/tex]
Comparing it with [tex]a+b\sqrt{2}[/tex], we get
a = 17, b = -12
