A survey of 500 adults aged 18 – 29 years of age revealed that 285 chose to eat fast food for dinner at least once in the past week. Find the sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week.

Question

09-07-2020
Mathematics

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A survey of 500 adults aged 18 – 29 years of age revealed that 285 chose to eat fast food for dinner at least once in the past week. Find the sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week.

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joaobezerra joaobezerra · Answer 1 · 2020-07-11T02:38:30+02:00

Answer:

The sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week is 0.57

Step-by-step explanation:

The sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week is:

The number of people who ate fast food for dinner at least once in the past week divided by the size of the sample.

In this question:

Sample of 500 adults.

Of those, 285 chose to eat fast food for dinner at least once in the past week.

285/500 = 0.57

The sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week is 0.57

ewomazinoade ewomazinoade · Answer 2 · 2022-03-29T15:46:41+02:00

The sample proportion of individuals surveyed who ate fast food for dinner at least once in the past week is 0.57.

What is the sample proportion?

The sample proportion is the ratio of the number of people who ate fast food for dinner at least once in the past week to the total number of people that partook in the survey.

Sample proportion = 285 / 500 = 0.57

To learn more about sample proportion, please check: https://brainly.com/question/21166113