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A football player of mass 103 kg running with a velocity of 2.0 m/s [E] collides head-
on with a 110 kg player on the opposing team travelling with a velocity of 3.2 m/s
[W]. Immediately after the collision the two players move in the same direction.
Calculate the final velocity of the two players.

Respuesta :

Answer:

The final velocity of the two players is 0.69 m/s in the direction of the opposing player.

Explanation:

Since the players are moving in opposite directions, from the principle of conservation of linear momentum;

[tex]m_{1} u_{1}[/tex] - [tex]m_{2}u_{2}[/tex] = [tex](m_{1} + m_{2} )[/tex] v

Where: [tex]m_{1}[/tex] is the mass of the first player, [tex]u_{1}[/tex] is the initial velocity of the first player, [tex]m_{2}[/tex] is the mass of the second player, [tex]u_{2}[/tex] is the initial velocity of the second player and v is the final common velocity of the two players after collision.

[tex]m_{1}[/tex] = 103 kg, [tex]u_{1}[/tex] = 2.0 m/s, [tex]m_{2}[/tex] = 110 kg, [tex]u_{2}[/tex] = 3.2 m/s. Thus;

103 × 2.0 - 110 × 3.2 = (103 + 110)v

206 - 352 = 213 v

-146 = 213 v

v = [tex]\frac{-146}{213}[/tex]

v = -0.69 m/s

The final velocity of the two players is 0.69 m/s in the direction of the opposing player.