Answer: Thus 663 J of heat is released when 27.6 g [tex]PCl_3[/tex] cools from 83.1 °C to 55.6 °C
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat released = ?
m = mass of substance = 27.6 g
C = specific heat capacity = [tex]0.874J/g^0C[/tex]
Initial temperature= [tex]T_i[/tex] = [tex]83.1^0C[/tex]
Final temperature = [tex]T_f[/tex] = [tex]55.6^0c[/tex]
Change in temperature ,[tex]\Delta T=T_f-T_i=(55.6-83.1)^0C=-27.5^0C[/tex]
Putting in the values, we get:
[tex]Q=27.6g\times 0.874J/g^0C\times -27.5^0C=-663J[/tex]
As the value of q is negative, it means the heat has been released and it is 663J
