Answer:
1.8L of CO2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2CO + O2 —> 2CO2
Next we shall determine the volume of O2 that reacted and the volume of CO2 produced from the balanced equation. This is illustrated below:
1 mole of O2 reacted
Recall: 1 mole of any gas occupy 22.4L at stp
Therefore 1 mole of O2 = 22.4L
2 moles of CO2 were produced
2 moles of CO2 = 2 x 22.4 = 44.8L
Summary:
From the balanced equation above,
22.4L of O2 reacted to produce 44.8L of CO2.
Finally, we shall determine the volume of CO2 produced from 0.90L of O2. This can be obtained as follow:
From the balanced equation above,
22.4L of O2 reacted to produce 44.8L of CO2.
Therefore, 0.90L of O2 will react to produce = (0.9 x 44.8)/22.4 = 1.8L of CO2.
Therefore, 1.8L of CO2 were produced.
