Respuesta :
Answer:
R=0
Step-by-step explanation:
f(x)=2x^3−x^2+x+1 is divided by 2x+1.
2 x^3 - x^2 + x + 1 = (x^2 - x + 1) × (2 x + 1) + 0
[(x^2 - x + 1) × (2 x + 1) + 0]/2x+1=x^2-x+1 the remainder is zero
The remainder is 0.
What are Arithmetic operations?
Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
f(x)=2x³−x²+x+1 is divided by 2x+1.
Consider 2x+1=0 ⇒2x = −1 ⇒ x= -1/2
By remainder theorem, When f(x) is divided by (2x+1)
Remainder (r) = f(-1/2)
f(-1/2) =2(-1/2)³−(-1/2)²+(-1/2)+1
f(-1/2) = -2/8 - 1/4 -1/2+1
f(-1/2) = - 1/4 - 1/4 -1/2+1
f(-1/2) = 0
Therefore, the remainder is 0.
Learn more about Arithmetic operations here:
brainly.com/question/25834626
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