marvelseoks
contestada

!! HELP PLEASE !! As seen from above, a 73.9 kg water skier is pulled by a 105 N force at a 22.5° angle, while the water creates a 74.8 N force pulling directly backward. What is the x-component of the total force on the skier?​

Respuesta :

fichoh

Answer: The x-component of the total force 97N

Explanation:

Given the following :

Mass (M) of skier = 73.9 kg

Pull force on the skier = 105N

Angle of pull = 22.5°

The direct backward force directly pulling the skier = 74.8N

the x-component of the total force on the skier

The horizontal component of the force = Magnitude of the pulling force × cosine of the angle of pull (FCosΘ)

FCosΘ = 105cos22.5°

105cos22.5 = 105 × 0.9238795

= 97.007350

= 97N

The backward force acting directly backward = 74.8N

Therefore, net x - component of the total force equals ;

97N - 74.8N = 22.2N

Otras preguntas