1) 9.8 cm
3) 194.68 kilo litters
Step By Step Explanation
Sister these questions are related to volume of cylinder.
You need to use this formula πr²h [ Where r is radius and h is height or depth]
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3)
Given:
Diameter = 4m
Therefore radius = 2m
Depth is 31/2 m
To Find:
How many kilo litters will it hold ?
Actually It's asking about Volume.
Solution:
You know, volume = πr²h
[tex] = \pi {(2 \: m)}^{2} \times ( \dfrac{31}{2})m[/tex]
[tex] = 3.14 \times 4 \: {m}^{2} \times \dfrac{31}{2} m[/tex]
[tex] = \: 62 \times 3.14 \times {m}^{3} \sf [\because \: {m}^{3} = kilolitters][/tex]
[tex] = \sf 194.68 \: \: kilolitters[/tex]
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1)
Given:
Diameter = 14 cm
[tex] \sf \therefore \: radius \: = 7 \: cm[/tex]
height = 20 cm
Diameter of other cylinder = 20 cm
[tex] \sf \therefore \: radius = 10 \: cm[/tex]
To Find:
Deep of water in other cylinder
Consider the depth of water be x
Solution:
Volume of water will remain constant in both
So,
[tex]V_1 = V_2[/tex]
[tex] \sf \: \pi {(r_1)}^{2} h_1 = \pi {( r_2 )}^{2} h_2[/tex]
[Eliminating π from both sides]
[tex] {(7)}^{2} \times 20= {(10)}^{2}x[/tex]
[tex]49 \times 20 = 100x [/tex]
[tex]x = \dfrac{49 \times 2}{10} [/tex]
[tex]x = \dfrac{98}{10} \implies \: 9.8[/tex]
Therefore the required value of x is 9.8 cm .
