Answer:
The answer is option 2.
Step-by-step explanation:
First, you have to find the height of the triangle using Cosine Rule, cosθ = adjacent/hypotenuse :
[tex]cos(θ) = \frac{adj.}{hypo.} [/tex]
[tex]θ = 30,adj. = h,hypo = 18[/tex]
[tex] \cos(30) = \frac{h}{18} [/tex]
[tex]18 \cos(30) = h[/tex]
[tex]h = 9 \sqrt{3} \: m[/tex]
Next, you have to find the area of triangle using Sin Rule, Area = 1/2×a×b×sinC where a, b represent the side length of the angle and C is the angle :
[tex]area = \frac{1}{2} \times a \times b \times sin(C)[/tex]
[tex]let \: a = 9 \sqrt{3} ,b = 18,C = 30[/tex]
[tex]area = \frac{1}{2} \times 9 \sqrt{3} \times 18 \times \sin(30) [/tex]
[tex]area = 70.1 \: {m}^{2} \: (near.tenth)[/tex]
