Answer:
x-y is parallel, im confused on what your asking for and what you mean by "negative"
Step-by-step explanation:
The equation of a line that is perpendicular to line g that contains (P, Q). is 3x − y = 3P − Q
The general form of the equation of a line with a slope m and passing through the point (x1, y1) is given as: y - y1 = m ( x- x1)
Further, this equation can be solved and simplified into the standard form of the equation of a line.
Given:
Line g passes through (3,6) and (0,5).
Slope of lone= y2 - y1/ (x2 - x1)
Perpendicular lines have opposite, reciprocal slopes, so negative change in x over change in y.
slope of line= -(-3 - 0)/(6 - 5)
= - -(-3)/1 =
slope of line = 3
Now, Two lines are perpendicular if they have the same slope.
Line parallel to line g has a slope of 1. Since it passes through (P, Q),
y - y1 = m ( x- x1)
y- Q =3 ( x- P)
y- Q = 3x- 3P
3x − y = 3P − Q
Learn more about equation of line here:.https://brainly.com/question/20519388
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