Answer:
[tex]\huge \boxed{28}[/tex]
Step-by-step explanation:
The trinomial is a perfect square.
Take the square root of the first term and the last term.
[tex](\sqrt{4x^2}+\sqrt{49})^2[/tex]
[tex]\sqrt{4x^2}=2x\\ \sqrt{49} =7[/tex]
[tex](2x+7)^2[/tex]
Expand to find the second term of the trinomial.
[tex](2x+7)(2x+7)\\2x(2x+7)+7(2x+7)\\4x^2 +14x+14x+49\\4x^2 +28x+49[/tex]
The second term of the trinomial is 28x.
