Answer:
[tex](\frac{4}{3},-\frac{10}{3})[/tex]
Step-by-step explanation:
If the extreme ends of a line segment AC are A[tex](x_1,y_1)[/tex] and C[tex](x_2,y_2)[/tex].
If a point B(x, y) divides the segment in the ratio of m : n
Then the coordinates of the point B are,
x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]
y = [tex]\frac{my_2+ny_1}{m+n}[/tex]
If the ends of AC are A(-2, 5) and C(2, -5) and a point B divides it in the ratio of m : n = 5 : 1
Therefore, coordinates of this point will be,
x = [tex]\frac{5\times (2)+1(-2)}{5+1}[/tex]
= [tex]\frac{10-2}{5+1}[/tex]
= [tex]\frac{8}{6}[/tex]
= [tex]\frac{4}{3}[/tex]
y = [tex]\frac{5\times (-5)+1(5)}{5+1}[/tex]
= [tex]\frac{-25+5}{6}[/tex]
= [tex]-\frac{20}{6}[/tex]
= [tex]-\frac{10}{3}[/tex]
Therefore, coordinates of the point B are [tex](\frac{4}{3},-\frac{10}{3})[/tex].
