Answer:
Step-by-step explanation:
Hello, please consider the following.
First, the numerator.
[tex](x+1)(\dfrac{1}{2\sqrt{x}})-\sqrt{x}=(x+1)\dfrac{\sqrt{x}}{2x}-\sqrt{x}\\\\=\dfrac{(x+1)\sqrt{x}-2x\sqrt{x}}{2x}=\dfrac{\sqrt{x}(x+1-2x)}{2x}\\\\=\dfrac{\sqrt{x}(1-x)}{2x}[/tex]
So it gives.
[tex]\dfrac{(x+1)(\dfrac{1}{2\sqrt{x}})-\sqrt{x}}{(x+1)^2}=\boxed{\dfrac{\sqrt{x}(1-x)}{2x(x+1)^2}}[/tex]
thanks.
