Answer:
The volume of hydrogen gas produced at s.t.p. is 9.419 dm³
Explanation:
The balanced chemical equation for the reaction is given as follows;
Zn + 2HCl → ZnCl₂ + H₂
Therefore, we have;
One mole of Zn reacts with 2 moles of HCl to produce one mole of ZnCl₂ and one mole of H₂
Number of moles of Zn present = 25/65 = 5/13 = 0.385 moles
Therefore, number of moles of H₂ produced = 0.385 moles
The volume of hydrogen gas produced is given by the relation
PV = nRT, we have;
R = 8.3145 J/(mol·K)
V = nRT/P = 0.385 ×8.3145 ×298.15/(101325)= 0.009419 m³ = 9.419 dm³
The volume of hydrogen gas produced at s.t.p. = 9.419 dm³.
