Answer:
solution,
let d and r denote democrats and republicans respectively.
given,
no. of total sample space n(s) =7+6=13
no. of total democrats n(d)=7
no. of total republicans n(r)=6
no. of democrats events n(D1)=2
no. of republicans events n(R1)=3
it is a mutually exclusive event. so the probability of selecting two democrats and three republicans= {n(D1)/n(s)} * {n(r1)/n(s)}
=(2/13)*(3/13)
=6/169
