Investigate the squared-and-ground-ended helical compression spring shown below to see if it is solid-safe. If not, what is the largest free length to which they can be wound using ns 1.2?
Wire diameter Outside coil diameter Free length Total coils Material
0.148 in 2.12 in 2.5 in 5.75 A227 hard-drawn steel

Respuesta :

Answer:

The spring is solid safe since calculated Ns >  given Ns

Explanation:

Given data :

Wire diameter (∝)= 0.148 in

outside coil diameter(OD) = 2.12 in

free length (lo) = 2.5 in

Total coil ( Nt )  = 5.75

material = A227 Hard-drawn steel

attached below is the remaining part of the detailed solution

From Table

A = 140 kpsi.i[tex]n^{m}[/tex], m = 0.190

Sut = A / [tex]d^{m}[/tex]

since given Ns = 1.2 < 1.36 (calculated Ns)   hence the spring is solid safe

Ver imagen batolisis
Ver imagen batolisis