Answer:
[tex] \boxed{\sf f(g(x)) = 6x -15 } [/tex]
Given:
[tex] \sf f(x) =2x + 3 \\ \sf g(x) = 3x - 9 [/tex]
To find:
[tex] \sf f(g(x)) [/tex]
Step-by-step explanation:
[tex] \sf Evaluate \ f(g (x)) \ by \ substituting \ in \ the \\ \sf value \ of \ g(x) \ into \ f(x): \\ \sf f(3x - 9) = 2(3x - 9) + 3 \\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sf = (2 \times 3x) - (2 \times 9) + 3 \\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sf = 6x - 18 + 3 \\ \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sf = 6x - 15 [/tex]
