Answer:
[tex]Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)[/tex]
Explanation:
Hello,
In this case, the molecular chemical reaction is written as:
[tex]2NH_4Br(aq)+Cu_2S(aq)\rightarrow 2CuBr(s)+(NH_4)_2SO_4(aq)[/tex]
In such a way, considering the net ionic notation and the solid yielded copper (I) bromide, we write:
[tex]2NH_4^+(aq)+Br^-(aq)+Cu^+(aq)+SO_4^{2-}(aq)\rightarrow CuBr(s)+NH_4^+(aq)+SO_4^{2-}(aq)[/tex]
Whereas ammonium and sulfate ions are spectator ions, therefore the net ionic equation is:
[tex]Br^-(aq)+Cu^+(aq)\rightarrow CuBr(s)[/tex]
Regards.
