Answer:
26) Let the first number be x.
Sum of three consecutive even numbers:
[tex]x+(x+2)+(x+4)=-84[/tex]
[tex]x+x+2+x+4=-84\\[/tex]
[tex]3x+6=-84[/tex]
Subtract 6 from both sides:
[tex]3x+6-6=-84-6[/tex]
[tex]3x=-90[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3}=\frac{-90}{3}[/tex]
[tex]x=-30[/tex]
To find the other two numbers, add 2 and 4 respectively:
[tex](-30+2=-28)(-30+4=-26)[/tex]
27) Let the first number be x.
Sum of three consecutive odd integers:
[tex]x+(x+2)+(x+4)=141[/tex]
[tex]3x+6=141[/tex]
Subtract 6 from both sides:
[tex]3x+6-6=141-6\\3x=135[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3}=\frac{135}{3}\\x=45[/tex]
To find the other two numbers, add 2 and 4 respectively:
[tex](45+2=47)(45+4=49)[/tex]
28) Let the first number be x.
Sum of four consecutive integers:
[tex]x+(x+1)+(x+2)+(x+3)=54[/tex]
[tex]4x+6=54[/tex]
Subtract 6 from both sides:
[tex]4x+6-6=54-6\\4x=48[/tex]
Divide both sides by 4:
[tex]\frac{4x}{4}=\frac{48}{4}\\x=12[/tex]
To find the other three numbers, add 1, 2 and 3 respectively:
[tex](12+1=13)(12+2=14)(12+3=15)[/tex]
29) Let the first number be x.
Sum of four consecutive integers:
[tex]x+(x+1)+(x+2)+(x+3)=-142[/tex]
[tex]4x+6=-142\\[/tex]
Subtract 6 from both sides:
[tex]4x+6-6=-142-6[/tex]
[tex]4x=-148[/tex]
Divide both sides by 4:
[tex]\frac{4x}{4}=\frac{-148}{4}\\x=-37[/tex]
To find the other three numbers, add 1, 2 and 3 respectively:
[tex](-37+1=-36)(-37+2=-35)(-37+3=-34)[/tex]
