100 mililiters of the 1 : 5 dilution must be transferred to the second microcentrifuge tube containing 900 mililiters buffer to prepare a 1 : 50 dilution. (Correct answer: B)
Reminder - The question has a typing mistake, correct form is presented below:
"How much fluid from the 1 : 5 dilution has to be transferred to the second microcentifuge tube containing 900 mL buffer to prepare a 1 : 50 dilution?"
We can estimate the quantity of the 1 : 5 dilution by means of the Principle of Mass Conservation and definition of Concentration, which are represented by the following expression:
[tex]c_{1}\cdot V_{1} = c_{2} \cdot V_{2}[/tex] (1)
Where:
If we know that [tex]c_{1} = \frac{1}{5}[/tex], [tex]V_{1} = x[/tex], [tex]c_{2} = \frac{1}{50}[/tex] and [tex]V_{2} = x + 900[/tex], then the amount to be transferred to the buffer is:
[tex]\frac{1}{5} \cdot x = \frac{1}{50}\cdot (x+900)[/tex]
[tex]10\cdot x = x + 900[/tex]
[tex]9\cdot x = 900[/tex]
[tex]x = 100[/tex]
100 mililiters of the 1 : 5 dilution must be transferred to the second microcentrifuge tube containing 900 mililiters buffer to prepare a 1 : 50 dilution. (Correct answer: B)
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