Answer:
x=-5
Step-by-step explanation:
don't think thats a quadratic equation, in that case the answer is above, just subtract from both sides
Answer:
x = ± i [tex]\sqrt{10}[/tex]
Step-by-step explanation:
[tex]x^{2} + 10 = 0[/tex]
Since this isn't a perfect square, we solve for x using the square root property.
Subtract 10 from each side.
[tex]x^{2} + 10 - 10 = 0 - 10[/tex]
[tex]x^{2} = - 10[/tex]
To solve fo x we need to take the square root of each side.
[tex]\sqrt{ x^{2} } = \sqrt{-10}[/tex]
[tex]x = \sqrt{-10}[/tex]
Because there is a negative under the square root sign we know there will be an imaginary number, i.
± i = [tex]\sqrt{-1}[/tex]
So we break it down more.
[tex]x = \sqrt{-1} *\sqrt{10}[/tex]
Because we know [tex]\sqrt{-1}[/tex] = i then we know x.
x = ± i [tex]\sqrt{10}[/tex]
Here we solve using the quadratic formula:
[tex]x = \frac{-b ± \sqrt{b^{2} -4ac} }{2a}[/tex] (ignore the A with the line over it)
a = 1 b = 0 c = 10
Plug in the values.
[tex]x = \frac{-0 ± \sqrt{0^{2} - 4*1*10} }{2*1}[/tex] (ignore the A again)
[tex]x = \frac{ ± \sqrt{- 40} }{2}[/tex] (keep ignoring the A with the hat)
If possible, you always want to look at your square root and see if any multiples of the number have a square root. In this case 4 has a square root of 2.
x = ± [tex]\frac{\sqrt{4}* \sqrt{-10} }{2}[/tex]
x = ± [tex]\frac{2\sqrt{-10} }{2}[/tex] 2/2 = 1 so it cancels
x = ± [tex]\sqrt{-10}[/tex]
Again we will have an imaginary number because [tex]\sqrt{-1}[/tex] = i
x = ±[tex]\sqrt{-1} \sqrt{10}[/tex]
x = ± i [tex]\sqrt{10}[/tex]
