Answer:
[tex]\rho = 2.7g/mL[/tex]
Explanation:
Hello,
In this case, given that the density for a material es defined via its mass and volume:
[tex]\rho =\frac{m}{V}[/tex]
We first need to compute the volume of aluminum in this case, since it comes from the volume of cylinder and the volume of the cylinder with the aluminum:
[tex]V=15.46 mL-10.00mL\\\\V=5.46mL[/tex]
In such a way, the density turns out:
[tex]\rho=\frac{14.74g}{5.46mL}\\ \\\rho = 2.7g/mL[/tex]
Best regards.