Answer:
a
The student does have enough evidence to refute the college claim
b
The null hypothesis is [tex]H_o : \mu \le 32[/tex]
The alternative hypothesis is [tex]H_a : \mu > 32[/tex]
Step-by-step explanation:
From the question we are told that
The average class size is [tex]\mu = 32[/tex]
The sample size is [tex]n = 40[/tex]
The sample mean is [tex]\= x = 34.8[/tex]
The standard deviation is [tex]\siigma = 99[/tex]
The significance level is [tex]\alpha = 0.10[/tex]
The null hypothesis is [tex]H_o : \mu \le 32[/tex]
The alternative hypothesis is [tex]H_a : \mu > 32[/tex]
Generally the test statistics is mathematically represented as
[tex]z =\frac{\= x - \mu}{ \frac{\sigma }{\sqrt{n} } }[/tex]
=> [tex]z = \frac{34.8 - 32}{ \frac{99 }{\sqrt{99} } }[/tex]
=> [tex]z = 0.1789 [/tex]
Generally the p-value is mathematically represented as
[tex]p- value = P (Z > 0.1789)[/tex]
From the z- table
[tex] P (Z > 0.1789) =0.42901 [/tex]
So
[tex]p- value = 0.42901 [/tex]
So from the calculation we can see that [tex]p- value > \alpha[/tex] so we fail to reject the null hypothesis
This means that the student does not have enough evidence to refute the college claim
