Respuesta :
The mole fration of ethanol and water in a sample of rectified spirit which contains 95% of ethanol by mass is 0.8 and 0.11.
How do we calculate mole fraction?
Mole fraction of any substance will be calculated by dividing the moles of that substance from the total moles of the solution.
Moles (n) will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given that 95% of ethanol by mass is present in the sample, so 95g of ethanol is present in 100g of solution.
Mass of solvent (water) = 100 - 95 = 5g
Moles of water = 5g / 18g/mol = 0.27mol
Moles of ethanol = 95g / 46g/mol = 2.06mol
Mole fraction of water = 0.27 / (0.27+2.06) = 0.11
Mole fraction of ethanol = 2.06 / (0.27+2.06) = 0.8
Hence required mole fraction of water & ethanol is 00.11 and 0.8 respectively.
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