Respuesta :
Answer:
(1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
Explanation:
(1). Given that,
Initial position = 0 m
Average speed = 0.50 m/s
Time = 3.0 s
We need to calculate the final position
Using formula of average speed
[tex]v_{av}=\dfrac{x_{f}+x_{i}}{t}[/tex]
Where, [tex]x_{f}[/tex] = final position
[tex]x_{i}[/tex] = Initial position
t = total time
Put the value into the formula
[tex]0.50=\dfrac{x_{f}+0}{3.0}[/tex]
[tex]x_{f}=0.50\times3.0[/tex]
[tex]x_{f}=1.5\ m[/tex]
(2). Given that,
Initial position = 0 m
Average speed = 0.75 m/s
Time = 4.0 s
We need to calculate the final position
Using formula of average speed
[tex]v_{av}=\dfrac{x_{f}+x_{i}}{t}[/tex]
Put the value into the formula
[tex]0.75=\dfrac{x_{f}+0}{4.0}[/tex]
[tex]x_{f}=0.75\times4.0[/tex]
[tex]x_{f}=3\ m[/tex]
(3). Given that,
Average speed = 1.25 m/s
Time = 3.0 sec
Initial position = 1.0 m
We need to calculate the final position
Using formula of average speed
[tex]v=\dfrac{x_{f}+x_{i}}{t}[/tex]
Put the value into the formula
[tex]1.25=\dfrac{x_{f}+1.0}{3.0}[/tex]
[tex]x_{f}=1.25\times3.0-1.0[/tex]
[tex]x_{f}=2.75\ m[/tex]
(4). Given that,
Average speed = 1.25 m/s
Distance = 100 m
We need to calculate the time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
Put the value into the formula
[tex]t=\dfrac{100}{1.25}[/tex]
[tex]t=80 sec[/tex]
(5). Given that,
Average speed = 5 miles/hr
Suppose, distance = 25 miles
We need to calculate the time
Using formula of time
[tex]t=\dfrac{d}{v}[/tex]
Put the value into the formula
[tex]t=\dfrac{25}{5}[/tex]
[tex]t=5\ hr[/tex]
Hence, (1). His final position is 1.5 m.
(2). The final position of the hedgehog is 3 m.
(3). The final position of the tortoise
(4). Her race time is 80 sec.
(5). It take to finish in 5 hr.
