Answer:
The approximate acceleration of the sled is 0.319 m/s²
Explanation:
Given;
mass of the sled, m = 90 kg
horizontal applied force, f = 258 N
angle of inclination of the force, θ = 15°
coefficient of kinetic friction of 0.250, μ = 0.25
The net vertical force on the sled is given by;
Fcosθ - μmg = ma
258Cos15 - (0.25 x 90 x 9.8) = ma
249.2 - 220.5 = ma
28.7 = ma
a = 28.7 /m
a = 28.7 / 90
a = 0.319 m/s²
Therefore, the approximate acceleration of the sled is 0.319 m/s²
