[tex] - 9 {x}^{2} + 3x = 0 [/tex]
[tex]3x( - 3x + 1) = 0[/tex]
[tex]3 x = 0 \\ x = 0[/tex]
And
[tex] - 3x + 1 = 0 \\ - 3x = - 1 \\ x = \frac{ - 1}{ - 3} \\ x = \frac{1}{3} [/tex]
So the x-intercepts are :
[tex]x = 0 \: \: \: \: \: and \: \: \: \: \: x = \frac{1}{3} \\ [/tex]
