Respuesta :
Answer:
35 minutes from 4:12 pm at 4:47 pm the tank will contain only 6617 liters of water.
Step-by-step explanation:
3:56-4:12 = -00:56 minutes passed
10452-8092=2360 liters of water lost
8092-6617=1475 liters
meaning: 56 mins lost 2360L
x mins lost 1475L
(the 2360 liters lost)/(the 56 minutes during which they were lost) is equal to the rate at which (the 1475 liters would be lost)/(the unknown amount of time)
2360/56 = 1475/x (cross multiply)
2360x = 1475(56)
2360x = 82600 (simplify)
x = 82600/2360 (divide to isolate x)
x = 35 (the unknown amount of time during which the water is lost)
4:12 pm plus 35 minutes is 4:47 pm.
The flow rate is the product of the speed of flow and the area through which the fluid flows
The time at which the tank will contain 6,617 L is 4:22 PM
Reason:
Known parameters are;
Volume of water in the tank at 3:56 PM = 10,452 L
Volume of water in the tank at 4:12 PM = 8,092 L
The rate at which water is flowing out of the tank, R, is given as follows;
- [tex]Flow \ rate, \, Q = \dfrac{10,452 - 8,092}{3:56 - 4:12 } = 147.5[/tex]
The flow rate, Q, of water out of the tank, Q = 147.5 L/min
The time it will take tank to contain 6,617 L, is given as follows;
Volume flow out = 10,452 L - 6,617 L = 3,835 L
The time it takes to flow to remain 6,617, t = [tex]\dfrac{3,835}{147.5} = 26[/tex]
It takes 26 minutes from the start before the water remaining is 6,617 L
Therefore, the time of the day, T = 3:56 PM + 26 minutes = 4:22 PM
- The time at which the tank will contain 6,617 L is at 4:22 PM
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