Answer:
[tex]{\huge{\pink{\underline{\underline{Solution:}}}}}[/tex]
In triangle,ADB
p(perpendicular)=BD=12 cm
h(hypotenuse)=AB=15cm
b(base)=AD=??
Let the AD be x
Using Pythagorean theorem,
[tex]{p}^{2} + {b}^{2} = {h}^{2} \\
=>{12}^{2} + {x}^{2} = {15}^{2} \\
=>144+{x}^{2}=225\\
=>{x}^{2}=225-144\\
=>{x}^{2}=81\\
=>x= \sqrt{81} \\
=>x= \sqrt{9×9} [/tex]
Hence,x=AD=9
So,AC=AD+DC=9+16=25.
