Answer:
There no sufficient evidence to support the manufactures claim at the 0.05 level
Step-by-step explanation:
From the question we are told that
The mean is [tex]\mu = 22100 \ miles[/tex]
The sample mean is [tex]\= x = 23400 \ miles[/tex]
The sample size is [tex]n = 18[/tex]
The standard deviation is [tex]\sigma = 1 500 miles[/tex]
The test statistics is [tex]t = 3.677[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
The null hypothesis is [tex]H_o : \mu = 22100[/tex]
The alternative hypothesis is [tex]H_a : \mu \ne 22100[/tex]
Generally the p-value is mathematically represented as
[tex]p-value = 2 * P(t >3.677 )[/tex]
From the z-table [tex]P(t >3.677 ) = 0.000118[/tex]
So
[tex]p-value = 2 * 0.000118[/tex]
=> [tex]p-value = 0.000236 [/tex]
From he value given and obtained we see that [tex]p-value < \alpha[/tex]
Hence we reject the null hypothesis
Hence there no sufficient evidence to support the manufactures claim