Given:
Diego pays $4.50 for 3 pounds of bananas and 2 pounds of oranges.
One pound of oranges cost $0.75 more than one pound of bananas.
To find:
The equation which represents the situation, and what is the price per pound of each fruit.
Solution:
Let b represent the price per pound of bananas.
Cost of 3 pound of banana = $3b
One pound of oranges cost $0.75 more than one pound of bananas.
So, cost of one pound of oranges = $(b+0.75)
Cost of 2 pound of oranges = $2(b+0.75)
Diego pays $4.50 for 3 pounds of bananas and 2 pounds of oranges.
[tex]3b+2(b+0.75)=4.50[/tex]
Therefore, the required equation is [tex]3b+2(b+0.75)=4.50[/tex].
On solving the above equation, we get
[tex]3b+2b+1.50=4.50[/tex]
[tex]5b=4.50-1.50[/tex]
[tex]5b=3[/tex]
Divide both sides by 5.
[tex]b=\dfrac{3}{5}[/tex]
[tex]b=0.60[/tex]
Now,
[tex]b+0.75=0.60+0.75=1.35[/tex]
Therefore, the price of fruits are $0.60 per bananas, $1.35 per pound of oranges.
Hence, the correct option is C.
