Answer:
238 kg/s
Explanation:
We are given;
Instantaneous Thrust; T = 7.26 × 10^(5) N
Exhaust speed; V_t = 3.05 × 10^(3) m/s
Now, the formula for the instantaneous thrust is given by;
T = V_t × ΔM/Δt
Since we are looking for mass of fuel the engine burns per second, then;
ΔM/Δt = T/V_t
Where ΔM/Δt is the mass of fuel burned per second.
Thus;
ΔM/Δt = (7.26 × 10^(5))/(3.05 × 10^(3))
ΔM/Δt ≈ 238 kg/s