Answer:
The radius of the blender is approximately 0.5041[tex]\bar 6[/tex] meters
Explanation:
The given parameters are;
The mass of the strawberry, m = 0.05 kg
The speed with which the strawberry is spun, v = 11.0 m/s
The centripetal force holding the strawberry = 12.0 N
The formula for the centripetal force, [tex]F_c[/tex], is given as follows;
[tex]F_c = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the centripetal rotation, which is the radius of the blender
[tex]\therefore r = \dfrac{m \cdot v^2}{F_c}[/tex]
Substituting the values gives;
[tex]\therefore r = \dfrac{0.05 \times 11^2}{12} = \dfrac{121}{240} \approx 0.5041 \bar 6[/tex]
The radius of the blender, r ≈ 0.5041[tex]\bar 6[/tex] meters.
