Respuesta :
Answer:
[tex]V=247L[/tex]
Explanation:
Hello there!
In this case, since the density is defined as the degree of compactness of a substance and is computed by diving the mass over the volume it occupies:
[tex]\rho =\frac{m}{V}[/tex]
Given the density and the mass of the neon, we can compute its density as shown below:
[tex]V=\frac{m}{\rho} =\frac{222g}{0.900g/L}\\\\V=247L[/tex]
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The volume of neon in liters is 246.67 L.
To calculate the volume of neon, we use the formula below.
Formula:
- D = m/V............... Equation 1
Where:
- D = Density of neon
- m = mass of neon
- V = Volume of neon.
make V the subject of the equation.
- V = m/D............... Equation 2
From the question,
Given:
- m = 222 g
- D = 0.900 g/L
Substitute these values into equation 2
- V = 222/0.9
- V = 246.67 L.
Hence, The volume of neon in liters is 246.67 L.
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