15 points. give me the method.
4.The difference of wavelength of two waves of frequencies 640Hz and 480Hz respectively in a certain medium is 1m. Find the velocity of sound in that medium.

Respuesta :

Answer:

[tex] \boxed{{160 \: m(s)}^{ - 1} }[/tex]

Explanation:

[tex]if \:the \: frequencies \: are \to \\ f_{1} = 640Hz \\ and \\f_{2} = 480Hz \: \\ but \: \boxed{v = f \gamma }: f = \frac{v}{ \gamma } \\ if \: \gamma_{1} - \gamma _{2} = 1 = \gamma \\ f_{1} - f_{2} = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 = \boxed{{160 \: m(s)}^{ - 1} }[/tex]