Answer:
Dx [sin3x] = 3cos3x
General Formulas and Concepts:
Calculus
- Chain Rule: [tex]\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
- Derivative of trig functions
- Basic Power Rule: f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
Step 1: Define
sin3x
Step 2: Find derivative
- Apply operative: Dx [sin3x]
- Chain Rule: cos3x · 3
- Simplify: 3cos3x
