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a train moving at a speed of 15 m/s is accelerated to 45 m/s over a 12 s period. what is the acceleration? ​

Respuesta :

MathPhys

Answer:

2.5 m/s²

Explanation:

Given:

v₀ = 15 m/s

v = 45 m/s

t = 12 s

Find: a

a = (v − v₀) / t

a = (45 m/s − 15 m/s) / 12 s

a = 2.5 m/s²

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