Answer:
none
Step-by-step explanation:
If (x + h) is a factor of f(x) then f(- h) = 0
Given
f(x) = [tex]x^{4}[/tex] + x³ - x² + x - 1
If (x + 1) is a factor then f(- 1) = 0
f(- 1) = [tex](-1)^{4}[/tex] + (- 1)³ - (- 1)² + (- 1) - 1 = 1 - 1 - 1 - 1 - 1 = - 3 ≠ 0
Thus (x + 1) is not a factor
If (x - 1) is a factor then f(1) = 0
f(1) = [tex]1^{4}[/tex] + 1³ - 1² + 1 - 1 = 1 + 1 - 1 + 1 - 1 = 1 ≠ 0
Thus (x - 1) is not a factor
