Answer:
Height of the pole = 9.17 chi.
Length of the rope = 12.17 chi.
Step-by-step explanation:
Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.
So, the length of the rope= x + 3 chi.
Let AB represents the pole in the figure, and one end of the rope is at point A.
When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.
The length of the rope = AC.
\Rightarrow AC=x+3 chi.
Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.
So, BC=8 chi.
As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,
[tex]AC^2= AB^2+BC^2[/tex]
[tex]\Rightarrow (x+3)^2=x^2+8^2[/tex]
[tex]\Rightarrow x^2+6x+9=x^2+64[/tex]
[tex]\Rightarrow 6x=64-9=55[/tex]
[tex]\Rightarrow x=55/6=9.17[/tex] chi.
Hence, the height of the pole, [tex]AB=x=9.17[/tex] chi,
and the length of the rope, [tex]x+3=9.17+3=12.17[/tex] chi.
