Answer
The value is [tex]I = 126000 \ kg \cdot m/s[/tex]
Explanation
From the question we are told that
The mass of the tank is [tex]m = 14000 \ kg[/tex]
The speed is [tex]u = 9 \ m/s[/tex]
The duration taken to bring it to a stop is [tex]\Delta t = 2.5 \ s[/tex]
Generally the impulse that was imparted on the tank is mathematically represented as
[tex]I = m (u - v )[/tex]
Generally the v is the final velocity of the tank which is v = 0 m/s , given that it was brought to rest
So
[tex]I = 14000 (9 - 0 )[/tex]
=> [tex]I = 126000 \ kg \cdot m/s[/tex]
Impulse is defined as the mass and change of velocity. The magnitude of the impulse was imparted to the tank 126000 Kg m/sec.
The force which acts on the body for a short interval of time is known as the impulsive force. The impulsive force is defined as the product of force and the duration for the force is applied.
It is denoted by I. Its unit is kgm/sec.
m is the mass of the tank = 14000 kg
v is the final speed = 9 m/s
u is the initial speed =0
t is the time interval = 2.5 sec.
The formula for impulse is given as ;
[tex]\rm I=\frac{m(v-u)}{t} \times t \\\\ \rm I=m(v-u) \\\\ \rm I=14000(9-0)\\\\\rm I= 126000 \;kgm/sec[/tex]
Hence the magnitude of the impulse was imparted to the tank 126000 Kg m/sec.
To learn more about the impulse refer to the link;
https://brainly.com/question/904448
