Step-by-step explanation:
Let the function is :
[tex]s(t)=3t^3-18t^2[/tex]
We need to find the velocity and acceleration functions
Velocity,
[tex]v=\dfrac{ds}{dt}\\\\v=\dfrac{d(3t^3-18t^2)}{dt}\\\\v=9t^2-36t[/tex]
Acceleration,
[tex]a=\dfrac{dv}{dt}\\\\a=\dfrac{d(9t^2-36t)}{dt}\\\\a=18t-36[/tex]
Hence, this is the required solution.