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In each table, y and x are in a proportional relationship.
Select the table with a constant of proportionality of –3.
A. 'x' is 1 2 3. 'y' is -3,-6,-9
B. 'x' is 1, 2, 3. 'y' is -1, -2, 0
C. 'x' is 1, 2, 3. 'y' is -3, -3, -3
D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1

In each table y and x are in a proportional relationship Select the table with a constant of proportionality of 3 A x is 1 2 3 y is 369 B x is 1 2 3 y is 1 2 0 class=

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Answer:

Hii! the answer is C.

Step-by-step explanation:

I did the quiz and got it right!

adioabiola

The table with a constant of proportionality of –3 are

A. 'x' is 1 2 3. 'y' is -3,-6,-9

A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3

A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1

y = k × x

where,

k = constant of proportionality

A. 'x' is 1 2 3. 'y' is -3,-6,-9

y = k × x

-3 = k × 1

- 3 = k

k = -3

B. 'x' is 1, 2, 3. 'y' is -1, -2, 0

y = k × x

-1 = k × 1

-1 = k

k = -1

C. 'x' is 1, 2, 3. 'y' is -3, -3, -3

y = k × x

-3 = k × 1

-3 = k

k = -3

D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1

y = k × x

-3 = k × 1

-3 = k

k = -3

or

y = k × x

-3/2 = k × 2

-3/ 2 = 2k

k = -3/2 ÷ 2

k = -3/2 × 1/2

k = -3

Therefore, the table with a constant of proportionality of –3 are

A. 'x' is 1 2 3. 'y' is -3,-6,-9

A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3

A. 'x' is 1 2 3. 'y' is -3,-6,-9 C. 'x' is 1, 2, 3. 'y' is -3, -3, -3D. 'x' is 1, 2, 3. 'y' is -3, -3/2, -1

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